{"id":"informator-maturalny-matematyka-2010/zad/34","paper_id":"informator-maturalny-matematyka-2010","number":"34","points":1,"ptype":"closed","subject":"matematyka","category":"informator-maturalny","year":2010,"month":null,"level":null,"text":"Zadanie 34. (1 pkt)\nPole kwadratu wpisanego w okrąg o promieniu 4 cm jest równe\nA. 64 cm2\nB. 32 cm2\nC. 16 cm2\nD. 8 cm2","answer":"B","answer_text":null,"solution":"Kwadrat wpisany w okrąg o promieniu 4: przekątna kwadratu = 2r = 8, bok a=8/sqrt(2)=4*sqrt(2), pole = a^2 = 32 cm^2. Odpowiedź: B.","image":"img/informator-maturalny-matematyka-2010/zad-34.webp","solution_image":null,"topics":null,"page_from":81,"source":"ai","answer_source":"ai","answer_text_source":null,"solution_source":"ai","text_source":"ocr","source_label":"Matematyka · Informator maturalny · 2010","subject_label":"Matematyka","category_label":"Informator maturalny","text_html":"<p>Zadanie 34. (1 pkt)<br>Pole kwadratu wpisanego w okrąg o promieniu 4 cm jest równe<br>A. 64 cm2<br>B. 32 cm2<br>C. 16 cm2<br>D. 8 cm2</p>","solutions":[{"source":"ai","label":"AI","kind":"text","html":"<p>Kwadrat wpisany w okrąg o promieniu 4: przekątna kwadratu = 2r = 8, bok a=8/sqrt(2)=4*sqrt(2), pole = a^2 = 32 cm^2. Odpowiedź: B.</p>"}]}