{"id":"informator-maturalny-matematyka-2010/zad/35","paper_id":"informator-maturalny-matematyka-2010","number":"35","points":1,"ptype":"closed","subject":"matematyka","category":"informator-maturalny","year":2010,"month":null,"level":null,"text":"Zadanie 35. (1 pkt)\nCiąg (\n)\nn\na\njest określony wzorem\n(\n) (\n)\n2\n3\n9\ndla\n1.\nn\nn\na\nn\nn\n⋅\n≥\nWynika stąd, że\nA.\n3\n81\na = -\nB.\n3\n27\na = -\nC.\n3\n0\na =\nD.\n3\n0\na >","answer":"C","answer_text":null,"solution":"a_n=(-3)^n*(9-n^2). a_3=(-3)^3*(9-9) = -27*0 = 0. Odpowiedź: C.","image":"img/informator-maturalny-matematyka-2010/zad-35.webp","solution_image":null,"topics":null,"page_from":81,"source":"ai","answer_source":"ai","answer_text_source":null,"solution_source":"ai","text_source":"ocr","source_label":"Matematyka · Informator maturalny · 2010","subject_label":"Matematyka","category_label":"Informator maturalny","text_html":"<p>Zadanie 35. (1 pkt)<br>Ciąg (<br>)<br>n<br>a<br>jest określony wzorem<br>(<br>) (<br>)<br>2<br>3<br>9<br>dla<br>1.<br>n<br>n<br>a<br>n<br>n<br>⋅<br>≥<br>Wynika stąd, że<br>A.<br>3<br>81<br>a = -<br>B.<br>3<br>27<br>a = -<br>C.<br>3<br>0<br>a =<br>D.<br>3<br>0<br>a &gt;</p>","solutions":[{"source":"ai","label":"AI","kind":"text","html":"<p>a_n=(-3)^n<em>(9-n^2). a_3=(-3)^3</em>(9-9) = -27*0 = 0. Odpowiedź: C.</p>"}]}