{"id":"matematyka-2012-czerwiec-probna-podstawowa/zad/1","paper_id":"matematyka-2012-czerwiec-probna-podstawowa","number":"1","points":1,"ptype":"closed","subject":"matematyka","category":"probna","year":2012,"month":"czerwiec","level":"podstawowa","text":"Zadanie 1. (1 pkt)\nLiczba\n3\n9\n1\n1\n12\n16\n27\nx\n\n\n\n\n\n\n\n\n\n\n\n. Wtedy\nA.\n11\nx \nB.\n17\nx \nC.\n19\nx \nD.\n25\nx ","answer":"C","answer_text":"2\n3\n4\n5\n6\n7\n8\n9\n10\n11\n12\n13","solution":null,"image":"img/matematyka-2012-czerwiec-probna-podstawowa/zad-1.webp","solution_image":null,"topics":"algebra","page_from":2,"source":"ocr","answer_source":null,"answer_text_source":"ocr","solution_source":null,"text_source":"ocr","source_label":"Matematyka · Matura próbna · czerwiec 2012 (podstawowa)","subject_label":"Matematyka","category_label":"Matura próbna","text_html":"

Zadanie 1. (1 pkt)
Liczba
3
9
1
1
12
16
27
x











. Wtedy
A.
11
x 
B.
17
x 
C.
19
x 
D.
25
x 

","answer_text_html":"

2
3
4
5
6
7
8
9
10
11
12
13

","solutions":[]}