{"id":"site-2653/zad/3137","paper_id":"site-2653","number":"3137","points":null,"ptype":"open","subject":"matematyka","category":"zbiory","year":0,"month":null,"level":"podstawowa","text":"Dane są długości boków |BC|=5 i |AC|=3 trójkąta prostokątnego ABC o kącie ostrym beta (zobacz rysunek). Wtedy A. sin beta = 3/5, B. sin beta = 4/5, C. sin beta = 3 pierwiastki z 34 / 34 D. sin beta = 5 pierwiastków z 34 / 34","answer":null,"answer_text":null,"solution":null,"image":"img/site/2653/zad-3137.svg","solution_image":"img/site/2653/rozw-3137.svg","topics":null,"page_from":null,"source":"site","answer_source":null,"answer_text_source":null,"solution_source":null,"text_source":"site","source_label":"Matematyka · Zbiory zadań (podstawowa)","subject_label":"Matematyka","category_label":"Zbiory zadań","text_html":"<p>Dane są długości boków |BC|=5 i |AC|=3 trójkąta prostokątnego ABC o kącie ostrym beta (zobacz rysunek). Wtedy A. sin beta = 3/5, B. sin beta = 4/5, C. sin beta = 3 pierwiastki z 34 / 34 D. sin beta = 5 pierwiastków z 34 / 34</p>","solutions":[{"source":"site","label":"matematykaszkolna.pl","kind":"image","image":"/img/site/2653/rozw-3137.svg"}]}